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    EATON AMA

    IT Discussion
    eaton ama
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    • JColeKenJ
      JColeKen Vendor @BRRABill
      last edited by

      @BRRABill There are a few things that go into it. One is the level of protection...that is typically the most important. Others included extended battery capability and network capability (many more, just naming a few). In some cases you may only require a certain level of protection and limited communication/extended run capability, so in those cases you'd be fine running a lower end UPS (less feature rich). But in general,we try to make it easy for someone off the street that knows nothing about UPS to be able to purchase protection for their "servers" and make sure that offering will provide them everything they would be required.

      BRRABillB 1 Reply Last reply Reply Quote 0
      • scottalanmillerS
        scottalanmiller @gbeyhaut
        last edited by

        @gbeyhaut said:

        @JaredBusch prices on the web!! NEVER! www.cdw.com should have some prices. To be honest we sell these primarily through electrical distributors like Wesco and Rexel.

        Even so, I think Jared is correct and getting MSRP prices or some guidance on pricing without needing to go to random online resellers. This presents a huge barrier to research and puts off IT departments. It works for IT that is being driven by their resellers, but not IT doing their own IT work.

        gbeyhautG 1 Reply Last reply Reply Quote 6
        • gbeyhautG
          gbeyhaut @scottalanmiller
          last edited by

          @scottalanmiller completely agree!

          1 Reply Last reply Reply Quote 1
          • windsoW
            windso Vendor @coliver
            last edited by windso

            @coliver

            Two easy ways, one hard way.

            Easy

            1. Add all your IT load wattages together. Done 😉

            2. For 120V loads, add all your currents per each "segment" and multiply them all by 120V. If you have three phases, the process is the same: take all the currents, add together, multiply by 120V. Done!

            3. For 208V loads, avoid the physics lessons. Take the current on each "segment" and multiply by 208V * SQRT(3). Done!

            For those math nerds out there SQRT of three is based off of 120deg phase angle from your unit circle. OK. There are great resources out there on three phase power, but don't make it too complicated. The above equations can get you there.

            coliverC dafyreD 2 Replies Last reply Reply Quote 3
            • dafyreD
              dafyre @JColeKen
              last edited by

              @JColeKen Yea, I kinda figured that. My family is chock full of Electricians... all I need is somebody to wire it up to my house's gas line and I'm golden, lol.

              JColeKenJ 1 Reply Last reply Reply Quote 0
              • BRRABillB
                BRRABill @JColeKen
                last edited by

                @JColeKen said:

                @BRRABill There are a few things that go into it. One is the level of protection...that is typically the most important. Others included extended battery capability and network capability (many more, just naming a few). In some cases you may only require a certain level of protection and limited communication/extended run capability, so in those cases you'd be fine running a lower end UPS (less feature rich). But in general,we try to make it easy for someone off the street that knows nothing about UPS to be able to purchase protection for their "servers" and make sure that offering will provide them everything they would be required.

                Could you give some details, say, in the difference between the 5S1500 and the 5P1500 that might sway a person either way?

                BRRABillB 1 Reply Last reply Reply Quote 0
                • coliverC
                  coliver @windso
                  last edited by

                  @windso said:

                  @coliver

                  Two easy ways, one hard way.

                  Easy

                  1. Add all your IT load wattages together. Done 😉

                  2. For 120V loads, take your server currents and multiply them all by 120V. If you have three phases, the process is the same: take all the currents, add together, multiply by 120V. Done!

                  3. For 208V loads, avoid the physics lessons. Take the current on each "segment" and multiply by 208V * SQRT(3). Done!

                  For those math nerds out there SQRT of three is based off of 120deg phase angle from your unit circle. OK. There are great resources out there on three phase power, but don't make it too complicated. The above equations can get you there.

                  Wow... that is the simplest I've come across, we are running 208v. Thanks.

                  1 Reply Last reply Reply Quote 1
                  • dafyreD
                    dafyre @windso
                    last edited by

                    @windso said:

                    1. Add all your IT load wattages together. Done 😉

                    Wattage of the Power Supplies, right?

                    1. For 120V loads, take your server currents and multiply them all by 120V. If you have three phases, the process is the same: take all the currents, add together, multiply by 120V. Done!

                    What do you mean by server currents?

                    art_of_shredA windsoW 2 Replies Last reply Reply Quote 0
                    • art_of_shredA
                      art_of_shred Banned @dafyre
                      last edited by

                      @dafyre said:

                      @windso said:

                      1. Add all your IT load wattages together. Done 😉

                      Wattage of the Power Supplies, right?

                      1. For 120V loads, take your server currents and multiply them all by 120V. If you have three phases, the process is the same: take all the currents, add together, multiply by 120V. Done!

                      What do you mean by server currents?

                      Current is amps. My question about the wattage is do you go by the labeled wattage of the power supply, or do you need to calculate the actual operating load?

                      JColeKenJ 1 Reply Last reply Reply Quote 1
                      • scottalanmillerS
                        scottalanmiller
                        last edited by

                        Server Current is the force of the flowing servers in the computational stream.

                        art_of_shredA dafyreD 2 Replies Last reply Reply Quote 0
                        • windsoW
                          windso Vendor @dafyre
                          last edited by

                          @dafyre , good point, I edit the wording. See above. Really I mean current on each phase. Poorly worded. Sorry!

                          1 Reply Last reply Reply Quote 1
                          • art_of_shredA
                            art_of_shred Banned @scottalanmiller
                            last edited by

                            @scottalanmiller said:

                            Server Current is the force of the flowing servers in the computational stream.

                            Don't try to answer electrical questions with IT answers. lol

                            1 Reply Last reply Reply Quote 3
                            • dafyreD
                              dafyre @scottalanmiller
                              last edited by

                              @scottalanmiller ❓ 💥 ❓ -- Mind = Blown

                              1 Reply Last reply Reply Quote 2
                              • JColeKenJ
                                JColeKen Vendor @dafyre
                                last edited by

                                @dafyre Cha-ching!

                                1 Reply Last reply Reply Quote 0
                                • JColeKenJ
                                  JColeKen Vendor @art_of_shred
                                  last edited by

                                  @art_of_shred Actual operating load is the most practical.

                                  coliverC art_of_shredA 2 Replies Last reply Reply Quote 0
                                  • coliverC
                                    coliver @JColeKen
                                    last edited by

                                    @JColeKen said:

                                    @art_of_shred Actual operating load is the most practical.

                                    How would you measure this in an environment without power monitoring? Or is it basically a guess at that point?

                                    art_of_shredA 1 Reply Last reply Reply Quote 0
                                    • art_of_shredA
                                      art_of_shred Banned @JColeKen
                                      last edited by

                                      @JColeKen said:

                                      @art_of_shred Actual operating load is the most practical.

                                      Is there a simple percentage to use there as a ballpark figure?

                                      JColeKenJ 1 Reply Last reply Reply Quote 0
                                      • art_of_shredA
                                        art_of_shred Banned @coliver
                                        last edited by

                                        @coliver said:

                                        @JColeKen said:

                                        @art_of_shred Actual operating load is the most practical.

                                        How would you measure this in an environment without power monitoring? Or is it basically a guess at that point?

                                        An ammeter works great if you have one and want real numbers.

                                        scottalanmillerS windsoW 2 Replies Last reply Reply Quote 1
                                        • JColeKenJ
                                          JColeKen Vendor @art_of_shred
                                          last edited by

                                          @art_of_shred 70-80% is a safe bet. Sometimes it is lower, but that is typically what I default to when sizing.

                                          1 Reply Last reply Reply Quote 2
                                          • scottalanmillerS
                                            scottalanmiller @art_of_shred
                                            last edited by

                                            @art_of_shred said:

                                            @coliver said:

                                            @JColeKen said:

                                            @art_of_shred Actual operating load is the most practical.

                                            How would you measure this in an environment without power monitoring? Or is it basically a guess at that point?

                                            An ammeter works great if you have one and want real numbers.

                                            Even in the afternoon or do you have to switch to a PMmeter?

                                            JColeKenJ art_of_shredA 2 Replies Last reply Reply Quote 1
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